5c^2=-(-2c^2)-(-6^2)

Solution for 5c^2=-(-2c^2)-(-6^2) equation:

5c^2=-(-2c^2)-(-6^2)

We move all terms to the left:

5c^2-(-(-2c^2)-(-6^2))=0


We calculate terms in parentheses: -(-(-2c^2)-(-6^2)), so:

-(-2c^2)-(-6^2)

We add all the numbers together, and all the variables

-(-2c^2)+36

We get rid of parentheses

2c^2+36

Back to the equation:

-(2c^2+36)


We get rid of parentheses

5c^2-2c^2-36=0

We add all the numbers together, and all the variables

3c^2-36=0

a = 3; b = 0; c = -36;
Δ = b2-4ac
Δ = 02-4·3·(-36)
Δ = 432
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{432}=\sqrt{144*3}=\sqrt{144}*\sqrt{3}=12\sqrt{3}$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{3}}{2*3}=\frac{0-12\sqrt{3}}{6}
=-\frac{12\sqrt{3}}{6}
=-2\sqrt{3}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{3}}{2*3}=\frac{0+12\sqrt{3}}{6}
=\frac{12\sqrt{3}}{6}
=2\sqrt{3}
$